Ankstesnis 1 2 3 Sekantis
me naam is m | Paskelbta: 07:36:45 2008 12 19 |
Pranešimai: 985 Temos: 37 Valstybė: Netherlands Lytis: Vyras |
yes LOL. but you didn't have that planet before.
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MBIK | Paskelbta: 09:40:37 2008 12 19 |
Pranešimai: 1832 Temos: 84 Valstybė: Lithuania Lytis: Vyras |
Iiridayn, perhaps it could be O(n(n-1)/2)?
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DAngel | Paskelbta: 10:35:28 2008 12 19 |
Pranešimai: 744 Temos: 57 Valstybė: United Kingdom |
What it means is a program isnt allowed to give commands back to the page... i.e. You not allowed to get a script to load a certain page and instruct an assault ship to attack a planet.
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DAngel | Paskelbta: 10:39:50 2008 12 19 |
Pranešimai: 744 Temos: 57 Valstybė: United Kingdom |
And for the record... All the software I made for indaGalaxy was done in pure Javascript meaning that the coding was freely available for everyone to see. There were no AJAX calls and there was no submitting information to the website for storing purposes.
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H911Reiver | Paskelbta: 11:38:46 2008 12 19 |
Pranešimai: 1939 Temos: 44 Valstybė: United States Lytis: Vyras |
MBIK:
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DAngel | Paskelbta: 12:00:29 2008 12 19 |
Pranešimai: 744 Temos: 57 Valstybė: United Kingdom |
and for those of us who looked at that and thought WTF
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H911Reiver | Paskelbta: 12:08:56 2008 12 19 |
Pranešimai: 1939 Temos: 44 Valstybė: United States Lytis: Vyras |
big 0 notation for dummies
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MBIK | Paskelbta: 12:22:15 2008 12 19 |
Pranešimai: 1832 Temos: 84 Valstybė: Lithuania Lytis: Vyras |
H911Reiver, thanks for the explanation. I agree that division by 2 is pointless (oh, did I write it?? ). I'd still prefer to write it as O(n^2 - n), although I must agree with you because I didn't know if there were rules about dropping insignificant parts... It's strange that nobody has taught me about it yet.
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Shadow Stalker | Paskelbta: 12:34:35 2008 12 19 |
Pranešimai: 11468 Temos: 322 Valstybė: United Kingdom Lytis: Vyras |
And in English this would all mean?
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MBIK | Paskelbta: 13:04:28 2008 12 19 |
Pranešimai: 1832 Temos: 84 Valstybė: Lithuania Lytis: Vyras |
That this problem is not really a problem, as n is limited to 50
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Ankstesnis 1 2 3 Sekantis